[수치해석] Simple Fixed Point 파이썬

import numpy as np
 
def fx(x):
  return np.exp(-1*x) - x
 
def gx(x):
  return np.exp(-1*x) 
 
def simple(x0, imax, es):
  iter = 1
  ea = 0
  xi = x0
 
  print("  i    xi      ea")
 
  while True:
    xold = xi
    xi = gx(xold)
    iter += 1
    ea = abs((xi - xold)/xi)*100
 
    print("%4d %.6f %.2f"%(iter, xi, ea))
    if iter >= imax or ea <= es:
      break
    
simple(0, 1000, 1.11)